$\sa{3213123}$ is a shortest superword for 3-shortperms since it contains all shortened 3-permutations $$\sa{32}, \sa{21}, \sa{13}, \sa{31}, \sa{12} \mbox{ and } \sa{23}.$$
Problem 125: Superwords of Shortened Permutations |
On the alphabet of natural numbers, a word is an $n$-permutation if every number from $\{\sa{1},\sa{2},\dots,n\}$ appears exactly once in it (see Problems 14 and 15). A word is a shortened $n$-permutation ($n$-shortperm, in short) if it is an $n$-permutation with its last element removed. The bijection between standard permutations and shortened ones for a given $n$ implies there are $n!$ shortened $n$-permutations.
The subject of the problem is the construction of a shortest superword for all $n$-shortperms. They are of length $n!+n-2$, which meets the obvious lower bound.