The words $\sa{abba}$ and $\sa{baab}$ are both palindromes and conjugate of each other. On the contrary, the word $\sa{aabaa}$ has no other conjugate palindrome, that is to say, its conjugacy class contains only one palindrome.
The conjugacy class of $\sa{abba}$, set $\{\sa{abba},\sa{bbaa},\sa{baab},\sa{aabb}\}$, contains only two palindromes. This is also the case for the word $(\sa{abba})^3$ whose conjugacy class contains $\sa{abbaab}\,\sa{baabba}$ and $\sa{baabba}\,\sa{abbaab}$, two palindromes. But the conjugacy class of $(\sa{abba})^2$ has only one palindrome among its four conjugates.
Problem 12: Conjugate Palindromes |
The problem is related to the two operations on words consisting of reversing a word and taking one of its conjugate. The operations are essentially incompatible in the sense that only a few conjugates of a word are also its reverse.
To examine the situation, we consider palindromes that are conjugates of each other.